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UHnkqh.json
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{
"data": {
"question": {
"questionId": "1000260",
"questionFrontendId": "剑指 Offer II 024",
"categoryTitle": "LCOF2",
"boundTopicId": 910263,
"title": "反转链表",
"titleSlug": "UHnkqh",
"content": "<p>English description is not available for the problem. Please switch to Chinese.</p>\n",
"translatedTitle": "反转链表",
"translatedContent": "<p>给定单链表的头节点 <code>head</code> ，请反转链表，并返回反转后的链表的头节点。</p>\n\n<div class=\"original__bRMd\">\n<div>\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/02/19/rev1ex1.jpg\" style=\"width: 302px; \" />\n<pre>\n<strong>输入：</strong>head = [1,2,3,4,5]\n<strong>输出：</strong>[5,4,3,2,1]\n</pre>\n\n<p><strong>示例 2：</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/02/19/rev1ex2.jpg\" style=\"width: 102px;\" />\n<pre>\n<strong>输入：</strong>head = [1,2]\n<strong>输出：</strong>[2,1]\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>head = []\n<strong>输出：</strong>[]\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li>链表中节点的数目范围是 <code>[0, 5000]</code></li>\n\t<li><code>-5000 <= Node.val <= 5000</code></li>\n</ul>\n\n<p> </p>\n\n<p><strong>进阶：</strong>链表可以选用迭代或递归方式完成反转。你能否用两种方法解决这道题？</p>\n</div>\n</div>\n\n<p> </p>\n\n<p><meta charset=\"UTF-8\" />注意：本题与主站 206 题相同： <a href=\"https://leetcode-cn.com/problems/reverse-linked-list/\">https://leetcode-cn.com/problems/reverse-linked-list/</a></p>\n",
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"difficulty": "Easy",
"likes": 60,
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"name": "Recursion",
"slug": "recursion",
"translatedName": "递归",
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"name": "Linked List",
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"code": "/**\n * Definition for singly-linked list.\n * struct ListNode {\n * int val;\n * ListNode *next;\n * ListNode() : val(0), next(nullptr) {}\n * ListNode(int x) : val(x), next(nullptr) {}\n * ListNode(int x, ListNode *next) : val(x), next(next) {}\n * };\n */\nclass Solution {\npublic:\n ListNode* reverseList(ListNode* head) {\n\n }\n};",
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"code": "/**\n * Definition for singly-linked list.\n * public class ListNode {\n * int val;\n * ListNode next;\n * ListNode() {}\n * ListNode(int val) { this.val = val; }\n * ListNode(int val, ListNode next) { this.val = val; this.next = next; }\n * }\n */\nclass Solution {\n public ListNode reverseList(ListNode head) {\n\n }\n}",
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"lang": "Python",
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"code": "# Definition for singly-linked list.\n# class ListNode(object):\n# def __init__(self, val=0, next=None):\n# self.val = val\n# self.next = next\nclass Solution(object):\n def reverseList(self, head):\n \"\"\"\n :type head: ListNode\n :rtype: ListNode\n \"\"\"",
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"code": "# Definition for singly-linked list.\n# class ListNode:\n# def __init__(self, val=0, next=None):\n# self.val = val\n# self.next = next\nclass Solution:\n def reverseList(self, head: ListNode) -> ListNode:",
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"code": "/**\n * Definition for singly-linked list.\n * struct ListNode {\n * int val;\n * struct ListNode *next;\n * };\n */\n\n\nstruct ListNode* reverseList(struct ListNode* head){\n\n}",
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"code": "/**\n * Definition for singly-linked list.\n * public class ListNode {\n * public int val;\n * public ListNode next;\n * public ListNode(int val=0, ListNode next=null) {\n * this.val = val;\n * this.next = next;\n * }\n * }\n */\npublic class Solution {\n public ListNode ReverseList(ListNode head) {\n\n }\n}",
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"lang": "JavaScript",
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"code": "/**\n * Definition for singly-linked list.\n * function ListNode(val, next) {\n * this.val = (val===undefined ? 0 : val)\n * this.next = (next===undefined ? null : next)\n * }\n */\n/**\n * @param {ListNode} head\n * @return {ListNode}\n */\nvar reverseList = function(head) {\n\n};",
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"lang": "Ruby",
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"code": "# Definition for singly-linked list.\n# class ListNode\n# attr_accessor :val, :next\n# def initialize(val = 0, _next = nil)\n# @val = val\n# @next = _next\n# end\n# end\n# @param {ListNode} head\n# @return {ListNode}\ndef reverse_list(head)\n\nend",
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"lang": "Swift",
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"code": "/**\n * Definition for singly-linked list.\n * public class ListNode {\n * public var val: Int\n * public var next: ListNode?\n * public init() { self.val = 0; self.next = nil; }\n * public init(_ val: Int) { self.val = val; self.next = nil; }\n * public init(_ val: Int, _ next: ListNode?) { self.val = val; self.next = next; }\n * }\n */\nclass Solution {\n func reverseList(_ head: ListNode?) -> ListNode? {\n\n }\n}",
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"lang": "Go",
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"code": "/**\n * Definition for singly-linked list.\n * type ListNode struct {\n * Val int\n * Next *ListNode\n * }\n */\nfunc reverseList(head *ListNode) *ListNode {\n\n}",
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"lang": "Scala",
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"code": "/**\n * Definition for singly-linked list.\n * class ListNode(_x: Int = 0, _next: ListNode = null) {\n * var next: ListNode = _next\n * var x: Int = _x\n * }\n */\nobject Solution {\n def reverseList(head: ListNode): ListNode = {\n\n }\n}",
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"lang": "Kotlin",
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"code": "/**\n * Example:\n * var li = ListNode(5)\n * var v = li.`val`\n * Definition for singly-linked list.\n * class ListNode(var `val`: Int) {\n * var next: ListNode? = null\n * }\n */\nclass Solution {\n fun reverseList(head: ListNode?): ListNode? {\n\n }\n}",
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"lang": "Rust",
"langSlug": "rust",
"code": "// Definition for singly-linked list.\n// #[derive(PartialEq, Eq, Clone, Debug)]\n// pub struct ListNode {\n// pub val: i32,\n// pub next: Option<Box<ListNode>>\n// }\n//\n// impl ListNode {\n// #[inline]\n// fn new(val: i32) -> Self {\n// ListNode {\n// next: None,\n// val\n// }\n// }\n// }\nimpl Solution {\n pub fn reverse_list(head: Option<Box<ListNode>>) -> Option<Box<ListNode>> {\n\n }\n}",
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"lang": "PHP",
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"code": "/**\n * Definition for a singly-linked list.\n * class ListNode {\n * public $val = 0;\n * public $next = null;\n * function __construct($val = 0, $next = null) {\n * $this->val = $val;\n * $this->next = $next;\n * }\n * }\n */\nclass Solution {\n\n /**\n * @param ListNode $head\n * @return ListNode\n */\n function reverseList($head) {\n\n }\n}",
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{
"lang": "TypeScript",
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"code": "/**\n * Definition for singly-linked list.\n * class ListNode {\n * val: number\n * next: ListNode | null\n * constructor(val?: number, next?: ListNode | null) {\n * this.val = (val===undefined ? 0 : val)\n * this.next = (next===undefined ? null : next)\n * }\n * }\n */\n\nfunction reverseList(head: ListNode | null): ListNode | null {\n\n};",
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{
"lang": "Racket",
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"code": "; Definition for singly-linked list:\n#|\n\n; val : integer?\n; next : (or/c list-node? #f)\n(struct list-node\n (val next) #:mutable #:transparent)\n\n; constructor\n(define (make-list-node [val 0])\n (list-node val #f))\n\n|#\n\n(define/contract (reverse-list head)\n (-> (or/c list-node? #f) (or/c list-node? #f))\n\n )",
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"lang": "Erlang",
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"code": "%% Definition for singly-linked list.\n%%\n%% -record(list_node, {val = 0 :: integer(),\n%% next = null :: 'null' | #list_node{}}).\n\n-spec reverse_list(Head :: #list_node{} | null) -> #list_node{} | null.\nreverse_list(Head) ->\n .",
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{
"lang": "Elixir",
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"code": "# Definition for singly-linked list.\n#\n# defmodule ListNode do\n# @type t :: %__MODULE__{\n# val: integer,\n# next: ListNode.t() | nil\n# }\n# defstruct val: 0, next: nil\n# end\n\ndefmodule Solution do\n @spec reverse_list(head :: ListNode.t | nil) :: ListNode.t | nil\n def reverse_list(head) do\n\n end\nend",
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