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NfY1m5.json
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{
"data": {
"question": {
"questionId": "1000441",
"questionFrontendId": "LCP 59",
"categoryTitle": "Algorithms",
"boundTopicId": 1443275,
"title": "搭桥过河",
"titleSlug": "NfY1m5",
"content": "",
"translatedTitle": "搭桥过河",
"translatedContent": "欢迎各位勇者来到力扣城，本次试炼主题为「搭桥过河」。\n\n勇者面前有一段长度为 `num` 的河流，河流可以划分为若干河道。每条河道上恰有一块浮木，`wood[i]` 记录了第 `i` 条河道上的浮木初始的覆盖范围。\n\n- 当且仅当浮木与相邻河道的浮木覆盖范围有重叠时，勇者才可以在两条浮木间移动\n- 勇者 **仅能在岸上** 通过花费一点「自然之力」，使任意一条浮木沿着河流移动一个单位距离\n\n请问勇者跨越这条河流，最少需要花费多少「自然之力」。\n\n\n**示例 1：**\n> 输入： `num = 10, wood = [[1,2],[4,7],[8,9]]`\n> 输出： `3`\n> 解释：如下图所示，\n> 将 [1,2] 浮木移动至 [3,4]，花费 2「自然之力」，\n> 将 [8,9] 浮木移动至 [7,8]，花费 1「自然之力」，\n> 此时勇者可以顺着 [3,4]->[4,7]->[7,8] 跨越河流，\n> 因此，勇者最少需要花费 3 点「自然之力」跨越这条河流\n.gif){:width=650px}\n\n\n**示例 2：**\n> 输入： `num = 10, wood = [[1,5],[1,1],[10,10],[6,7],[7,8]]`\n> 输出： `10`\n> 解释：\n> 将 [1,5] 浮木移动至 [2,6]，花费 1「自然之力」，\n> 将 [1,1] 浮木移动至 [6,6]，花费 5「自然之力」，\n> 将 [10,10] 浮木移动至 [6,6]，花费 4「自然之力」，\n> 此时勇者可以顺着 [2,6]->[6,6]->[6,6]->[6,7]->[7,8] 跨越河流，\n> 因此，勇者最少需要花费 10 点「自然之力」跨越这条河流\n\n\n**示例 3：**\n> 输入： `num = 5, wood = [[1,2],[2,4]]`\n> 输出： `0`\n> 解释：勇者不需要移动浮木，仍可以跨越这条河流\n\n**提示:**\n- `1 <= num <= 10^9`\n- `1 <= wood.length <= 10^5`\n- `wood[i].length == 2`\n- `1 <= wood[i][0] <= wood[i][1] <= num`\n\n",
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"username": "LeetCode",
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{
"lang": "C++",
"langSlug": "cpp",
"code": "class Solution {\npublic:\n long long buildBridge(int num, vector<vector<int>>& wood) {\n\n }\n};",
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"code": "class Solution(object):\n def buildBridge(self, num, wood):\n \"\"\"\n :type num: int\n :type wood: List[List[int]]\n :rtype: int\n \"\"\"",
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"code": "public class Solution {\n public long BuildBridge(int num, int[][] wood) {\n\n }\n}",
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"code": "/**\n * @param {number} num\n * @param {number[][]} wood\n * @return {number}\n */\nvar buildBridge = function(num, wood) {\n\n};",
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"code": "# @param {Integer} num\n# @param {Integer[][]} wood\n# @return {Integer}\ndef build_bridge(num, wood)\n\nend",
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"lang": "PHP",
"langSlug": "php",
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