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M99OJA.json
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{
"data": {
"question": {
"questionId": "1000240",
"questionFrontendId": "剑指 Offer II 086",
"categoryTitle": "LCOF2",
"boundTopicId": 910245,
"title": "分割回文子字符串",
"titleSlug": "M99OJA",
"content": "<p>English description is not available for the problem. Please switch to Chinese.</p>\n",
"translatedTitle": "分割回文子字符串",
"translatedContent": "<p>给定一个字符串 <code>s</code> ，请将 <code>s</code> 分割成一些子串，使每个子串都是 <strong>回文串</strong> ，返回 s 所有可能的分割方案。</p>\n\n<p><meta charset=\"UTF-8\" /><strong>回文串</strong> 是正着读和反着读都一样的字符串。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>s =<strong> </strong>"google"\n<strong>输出：</strong>[["g","o","o","g","l","e"],["g","oo","g","l","e"],["goog","l","e"]]\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>s = "aab"\n<strong>输出：</strong>[["a","a","b"],["aa","b"]]\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>s = "a"\n<strong>输出：</strong>[["a"]]</pre>\n\n<p> </p>\n\n<p><b>提示：</b></p>\n\n<ul>\n\t<li><code>1 <= s.length <= 16</code></li>\n\t<li><code>s </code>仅由小写英文字母组成</li>\n</ul>\n\n<p> </p>\n\n<p><meta charset=\"UTF-8\" />注意：本题与主站 131 题相同： <a href=\"https://leetcode-cn.com/problems/palindrome-partitioning/\">https://leetcode-cn.com/problems/palindrome-partitioning/</a></p>\n",
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{
"lang": "C++",
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"code": "class Solution {\npublic:\n vector<vector<string>> partition(string s) {\n\n }\n};",
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"code": "class Solution(object):\n def partition(self, s):\n \"\"\"\n :type s: str\n :rtype: List[List[str]]\n \"\"\"",
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"code": "\n\n/**\n * Return an array of arrays of size *returnSize.\n * The sizes of the arrays are returned as *returnColumnSizes array.\n * Note: Both returned array and *columnSizes array must be malloced, assume caller calls free().\n */\nchar*** partition(char* s, int* returnSize, int** returnColumnSizes){\n\n}",
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{
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"shortDescription": "通行全球的程序员经典面试秘籍",
"fullDescription": "本书精选国内外名企高频面试题并深度拓展，系统地总结了程序员面试中必备的数据结构与算法知识，并以面试者及面试官的双向视角剖析考点与解题思路，适合所有正在准备面试的程序员阅读。",
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