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M1oyTv.json
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{
"data": {
"question": {
"questionId": "1000253",
"questionFrontendId": "剑指 Offer II 017",
"categoryTitle": "LCOF2",
"boundTopicId": 910256,
"title": "含有所有字符的最短字符串",
"titleSlug": "M1oyTv",
"content": "<p>English description is not available for the problem. Please switch to Chinese.</p>\n",
"translatedTitle": "含有所有字符的最短字符串",
"translatedContent": "<p>给定两个字符串 <code>s</code> 和 <code>t</code> 。返回 <code>s</code> 中包含 <code>t</code> 的所有字符的最短子字符串。如果 <code>s</code> 中不存在符合条件的子字符串，则返回空字符串 <code>""</code> 。</p>\n\n<p>如果 <code>s</code> 中存在多个符合条件的子字符串，返回任意一个。</p>\n\n<p> </p>\n\n<p><strong>注意： </strong>对于 <code>t</code> 中重复字符，我们寻找的子字符串中该字符数量必须不少于 <code>t</code> 中该字符数量。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>s = "ADOBECODEBANC", t = "ABC"\n<strong>输出：</strong>"BANC" \n<strong>解释：</strong>最短子字符串 "BANC" 包含了字符串 t 的所有字符 'A'、'B'、'C'</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>s = "a", t = "a"\n<strong>输出：</strong>"a"\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>s = "a", t = "aa"\n<strong>输出：</strong>""\n<strong>解释：</strong>t 中两个字符 'a' 均应包含在 s 的子串中，因此没有符合条件的子字符串，返回空字符串。</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 <= s.length, t.length <= 10<sup>5</sup></code></li>\n\t<li><code>s</code> 和 <code>t</code> 由英文字母组成</li>\n</ul>\n\n<p> </p>\n\n<p><strong>进阶：</strong>你能设计一个在 <code>o(n)</code> 时间内解决此问题的算法吗？</p>\n\n<p> </p>\n\n<p><meta charset=\"UTF-8\" />注意：本题与主站 76 题相似（本题答案不唯一）：<a href=\"https://leetcode-cn.com/problems/minimum-window-substring/\">https://leetcode-cn.com/problems/minimum-window-substring/</a></p>\n",
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"username": "LeetCode",
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"name": "Hash Table",
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"translatedName": "哈希表",
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"slug": "string",
"translatedName": "字符串",
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{
"name": "Sliding Window",
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"code": "class Solution {\npublic:\n string minWindow(string s, string t) {\n\n }\n};",
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"lang": "Erlang",
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"__typename": "CodeSnippetNode"
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{
"lang": "Elixir",
"langSlug": "elixir",
"code": "defmodule Solution do\n @spec min_window(s :: String.t, t :: String.t) :: String.t\n def min_window(s, t) do\n\n end\nend",
"__typename": "CodeSnippetNode"
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"hints": [],
"solution": null,
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"sampleTestCase": "\"ADOBECODEBANC\"\n\"ABC\"",
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