6CE719.json

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        "question": {
            "questionId": "1000476",
            "questionFrontendId": "LCP 61",
            "categoryTitle": "Algorithms",
            "boundTopicId": 1845919,
            "title": "气温变化趋势",
            "titleSlug": "6CE719",
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            "translatedTitle": "气温变化趋势",
            "translatedContent": "力扣城计划在两地设立「力扣嘉年华」的分会场，气象小组正在分析两地区的气温变化趋势，对于第 `i ~ (i+1)` 天的气温变化趋势，将根据以下规则判断：\n- 若第 `i+1` 天的气温 **高于** 第 `i` 天，为 **上升** 趋势\n- 若第 `i+1` 天的气温 **等于** 第 `i` 天，为 **平稳** 趋势\n- 若第 `i+1` 天的气温 **低于** 第 `i` 天，为 **下降** 趋势\n\n已知 `temperatureA[i]` 和 `temperatureB[i]` 分别表示第 `i` 天两地区的气温。\n组委会希望找到一段天数尽可能多，且两地气温变化趋势相同的时间举办嘉年华活动。请分析并返回两地气温变化趋势**相同的最大连续天数**。\n> 即最大的 `n`，使得第 `i~i+n` 天之间，两地气温变化趋势相同\n\n**示例 1：**\n>输入：\n>`temperatureA = [21,18,18,18,31]`\n>`temperatureB = [34,32,16,16,17]`\n>\n>输出：`2`\n>\n>解释：如下表所示， 第 `2～4` 天两地气温变化趋势相同，且持续时间最长，因此返回 `4-2=2`\n![image.png](https://pic.leetcode-cn.com/1663902654-hlrSvs-image.png){:width=1000px}\n\n\n**示例 2：**\n>输入：\n>`temperatureA = [5,10,16,-6,15,11,3]`\n>`temperatureB = [16,22,23,23,25,3,-16]`\n>\n>输出：`3`\n\n**提示：**\n- `2 <= temperatureA.length == temperatureB.length <= 1000`\n- `-20 <= temperatureA[i], temperatureB[i] <= 40`\n",
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                    "lang": "C++",
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                    "code": "class Solution {\npublic:\n    int temperatureTrend(vector<int>& temperatureA, vector<int>& temperatureB) {\n\n    }\n};",
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                    "code": "class Solution(object):\n    def temperatureTrend(self, temperatureA, temperatureB):\n        \"\"\"\n        :type temperatureA: List[int]\n        :type temperatureB: List[int]\n        :rtype: int\n        \"\"\"",
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                    "code": "# @param {Integer[]} temperature_a\n# @param {Integer[]} temperature_b\n# @return {Integer}\ndef temperature_trend(temperature_a, temperature_b)\n\nend",
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