Tschirnhausen cubic

In geometry, the Tschirnhausen cubic is a plane curve defined by the polar equation

$r=a\sec ^{3}(\theta /3).$

The Tschirnhausen cubic, $y^{2}=x^{3}+3x^{2}.$

History

The curve was studied by von Tschirnhaus, de L'Hôpital and Catalan. It was given the name Tschirnhausen cubic in a 1900 paper by R C Archibald, though it is sometimes known as de L'Hôpital's cubic or the trisectrix of Catalan.

Other equations

Put $t=\tan(\theta /3)$. Then applying triple-angle formulas gives

$x=a\cos \theta \sec ^{3}{\frac {\theta }{3}}=a(\cos ^{3}{\frac {\theta }{3}}-3\cos {\frac {\theta }{3}}\sin ^{2}{\frac {\theta }{3}})\sec ^{3}{\frac {\theta }{3}}$

$=a\left(1-3\tan ^{2}{\frac {\theta }{3}}\right)=a(1-3t^{2})$

$y=a\sin \theta \sec ^{3}{\frac {\theta }{3}}=a\left(3\cos ^{2}{\frac {\theta }{3}}\sin {\frac {\theta }{3}}-\sin ^{3}{\frac {\theta }{3}}\right)\sec ^{3}{\frac {\theta }{3}}$

$=a\left(3\tan {\frac {\theta }{3}}-\tan ^{3}{\frac {\theta }{3}}\right)=at(3-t^{2})$

giving a parametric form for the curve. The parameter t can be eliminated easily giving the Cartesian equation

$27ay^{2}=(a-x)(8a+x)^{2}$.

If the curve is translated horizontally by 8a then the equations become

$x=3a(3-t^{2})$

$y=at(3-t^{2})$

or

$x^{3}=9a\left(x^{2}-3y^{2}\right)$.

This gives an alternate polar form of

$r=9a\left(\sec \theta -3\sec \theta \tan ^{2}\theta \right)$.

References

• J. D. Lawrence, A Catalog of Special Plane Curves. New York: Dover, 1972, pp. 87-90.

External links

• Weisstein, Eric W. "Tschirnhausen Cubic". MathWorld.
• "Tschirnhaus' Cubic" at MacTutor History of Mathematics Archive
• "Cubique de Tschirnhausen" at Encyclopédie des Formes Mathématiques Remarquables (in French)