find_objects#
- scipy.ndimage.find_objects(input, max_label=0)[source]#
Find objects in a labeled array.
- Parameters:
- inputndarray of ints
Array containing objects defined by different labels. Labels with value 0 are ignored.
- max_labelint, optional
Maximum label to be searched for in input. If max_label is not given, the positions of all objects are returned.
- Returns:
- object_sliceslist of tuples
A list of tuples, with each tuple containing N slices (with N the dimension of the input array). Slices correspond to the minimal parallelepiped that contains the object. If a number is missing, None is returned instead of a slice. The label
l
corresponds to the indexl-1
in the returned list.
See also
Notes
This function is very useful for isolating a volume of interest inside a 3-D array, that cannot be “seen through”.
Array API Standard Support
find_objects
has experimental support for Python Array API Standard compatible backends in addition to NumPy. Please consider testing these features by setting an environment variableSCIPY_ARRAY_API=1
and providing CuPy, PyTorch, JAX, or Dask arrays as array arguments. The following combinations of backend and device (or other capability) are supported.Library
CPU
GPU
NumPy
✅
n/a
CuPy
n/a
⛔
PyTorch
✅
⛔
JAX
⚠️ no JIT
⛔
Dask
⚠️ computes graph
n/a
See Support for the array API standard for more information.
Examples
>>> from scipy import ndimage >>> import numpy as np >>> a = np.zeros((6,6), dtype=int) >>> a[2:4, 2:4] = 1 >>> a[4, 4] = 1 >>> a[:2, :3] = 2 >>> a[0, 5] = 3 >>> a array([[2, 2, 2, 0, 0, 3], [2, 2, 2, 0, 0, 0], [0, 0, 1, 1, 0, 0], [0, 0, 1, 1, 0, 0], [0, 0, 0, 0, 1, 0], [0, 0, 0, 0, 0, 0]]) >>> ndimage.find_objects(a) [(slice(2, 5, None), slice(2, 5, None)), (slice(0, 2, None), slice(0, 3, None)), (slice(0, 1, None), slice(5, 6, None))] >>> ndimage.find_objects(a, max_label=2) [(slice(2, 5, None), slice(2, 5, None)), (slice(0, 2, None), slice(0, 3, None))] >>> ndimage.find_objects(a == 1, max_label=2) [(slice(2, 5, None), slice(2, 5, None)), None]
>>> loc = ndimage.find_objects(a)[0] >>> a[loc] array([[1, 1, 0], [1, 1, 0], [0, 0, 1]])