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adding-two-negabinary-numbers.json
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{
"data": {
"question": {
"questionId": "1148",
"questionFrontendId": "1073",
"categoryTitle": "Algorithms",
"boundTopicId": 6732,
"title": "Adding Two Negabinary Numbers",
"titleSlug": "adding-two-negabinary-numbers",
"content": "<p>Given two numbers <code>arr1</code> and <code>arr2</code> in base <strong>-2</strong>, return the result of adding them together.</p>\n\n<p>Each number is given in <em>array format</em>: as an array of 0s and 1s, from most significant bit to least significant bit. For example, <code>arr = [1,1,0,1]</code> represents the number <code>(-2)^3 + (-2)^2 + (-2)^0 = -3</code>. A number <code>arr</code> in <em>array, format</em> is also guaranteed to have no leading zeros: either <code>arr == [0]</code> or <code>arr[0] == 1</code>.</p>\n\n<p>Return the result of adding <code>arr1</code> and <code>arr2</code> in the same format: as an array of 0s and 1s with no leading zeros.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> arr1 = [1,1,1,1,1], arr2 = [1,0,1]\n<strong>Output:</strong> [1,0,0,0,0]\n<strong>Explanation: </strong>arr1 represents 11, arr2 represents 5, the output represents 16.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> arr1 = [0], arr2 = [0]\n<strong>Output:</strong> [0]\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> arr1 = [0], arr2 = [1]\n<strong>Output:</strong> [1]\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 <= arr1.length, arr2.length <= 1000</code></li>\n\t<li><code>arr1[i]</code> and <code>arr2[i]</code> are <code>0</code> or <code>1</code></li>\n\t<li><code>arr1</code> and <code>arr2</code> have no leading zeros</li>\n</ul>\n",
"translatedTitle": "负二进制数相加",
"translatedContent": "<p>给出基数为 <strong>-2</strong> 的两个数 <code>arr1</code> 和 <code>arr2</code>，返回两数相加的结果。</p>\n\n<p>数字以 <em>数组形式</em><strong> </strong>给出：数组由若干 0 和 1 组成，按最高有效位到最低有效位的顺序排列。例如，<code>arr = [1,1,0,1]</code> 表示数字 <code>(-2)^3 + (-2)^2 + (-2)^0 = -3</code>。<em>数组形式</em> 中的数字 <code>arr</code> 也同样不含前导零：即 <code>arr == [0]</code> 或 <code>arr[0] == 1</code>。</p>\n\n<p>返回相同表示形式的 <code>arr1</code> 和 <code>arr2</code> 相加的结果。两数的表示形式为：不含前导零、由若干 0 和 1 组成的数组。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>arr1 = [1,1,1,1,1], arr2 = [1,0,1]\n<strong>输出：</strong>[1,0,0,0,0]\n<strong>解释：</strong>arr1 表示 11，arr2 表示 5，输出表示 16 。\n</pre>\n\n<p><meta charset=\"UTF-8\" /></p>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>arr1 = [0], arr2 = [0]\n<strong>输出：</strong>[0]\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>arr1 = [0], arr2 = [1]\n<strong>输出：</strong>[1]\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n<meta charset=\"UTF-8\" />\n\n<ul>\n\t<li><code>1 <= arr1.length, arr2.length <= 1000</code></li>\n\t<li><code>arr1[i]</code> 和 <code>arr2[i]</code> 都是 <code>0</code> 或 <code>1</code></li>\n\t<li><code>arr1</code> 和 <code>arr2</code> 都没有前导0</li>\n</ul>\n",
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"code": "class Solution {\npublic:\n vector<int> addNegabinary(vector<int>& arr1, vector<int>& arr2) {\n\n }\n};",
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"code": "class Solution(object):\n def addNegabinary(self, arr1, arr2):\n \"\"\"\n :type arr1: List[int]\n :type arr2: List[int]\n :rtype: List[int]\n \"\"\"",
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"code": "/**\n * @param {number[]} arr1\n * @param {number[]} arr2\n * @return {number[]}\n */\nvar addNegabinary = function(arr1, arr2) {\n\n};",
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"code": "class Solution {\n\n /**\n * @param Integer[] $arr1\n * @param Integer[] $arr2\n * @return Integer[]\n */\n function addNegabinary($arr1, $arr2) {\n\n }\n}",
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"code": "# @param {Integer[]} arr1\n# @param {Integer[]} arr2\n# @return {Integer[]}\ndef add_negabinary(arr1, arr2)\n\nend",
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"lang": "Erlang",
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"code": "defmodule Solution do\n @spec add_negabinary(arr1 :: [integer], arr2 :: [integer]) :: [integer]\n def add_negabinary(arr1, arr2) do\n \n end\nend",
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"hints": [
"We can try to determine the last digit of the answer, then divide everything by 2 and repeat."
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